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Nice article. I think this example will better than when run in Console tab of browser.
let y = 7;
y++;
//result: 7
y++;
//result: 8
console.log(y);
//result: 9
Hi! What will be the explaination for this set of codes: var a = 10; var b = 10; sum = Math.log2(2a * 2b); console.log(sum); sum = 20;
Tania , your tutorials are very nice. In the addition and subtraction section Please include this example for scrollToId function.
<!DOCTYPE html> <html lang=“en”> <head> <meta charset=“UTF-8”> <title>Title</title> <style> div { border: 1px solid black; background-color: lightblue; height: 2000px; width: 2000px; } </style> </head> <body>
<button onclick=“myFunction()” style=“position:fixed;”>Click me to go down</button><br><br> <button onclick=“scrollToId()” style=“position:fixed;”>Click me to go up</button><br><br> <div></div>
<script> function scrollToId() { const navHeight = 100; window.scrollTo(0, window.pageYOffset - navHeight); }
function myFunction() { window.scrollTo(0, 100); alert("pageXOffset: " + window.pageXOffset + ", pageYOffset: " + window.pageYOffset); } </script>
</body> </html>
Thank you .
I think this explanation has a mistake(or ambiguity).
Set a variable
let y = 7;
// Use the prefix increment operation
let postfix = y++;
console.log(postfix);
Output
7
The value of y was not increased in the postfix operation. This is because the value will not be incremented until after the expression has been evaluated.
Actually, when using the postfix ++ operator the value of y gets updated but what is returned to the left-hand side is the old value of y.
let postfix=y++;
//can be thought of
//let postfix=y;
//y=y+1;